Chemical Properties of Alcohols

Acid catalyzed hydration of alkenes except ethene leads to the formation of

The main product of the following reactions is

${\mathrm{C}}_6{\mathrm{H}}_5{\mathrm{CH}}_2\mathrm{CH}\left(\mathrm{OH}\right)\mathrm{CH}{\left({\mathrm{CH}}_3\right)}_2\stackrel{\mathrm{Conc}. {\mathrm{H}}_2{\mathrm{SO}}_4}{\to }$       ?

During dehydration of alcohols to alkenes by heating with concentrated  ${\mathrm{H}}_2{\mathrm{SO}}_4$ the initiation step is –

Select the correct configuration for product.

In the given elimination reactions which can be taken as example(s) of regioselective but not stereo selective

Complete the following reaction sequences by writing structural formulae by writing organic compounds $\mathrm{A}, \mathrm{B} \mathrm{and} \mathrm{C}$.

$$\begin{gathered} \mathrm{a}. 2-\mathrm{bromobutane}\stackrel{\mathrm{Alc}. \mathrm{KOH}}{\to }\mathrm{A}\stackrel{{\mathrm{Br}}_2}{\to }\mathrm{B}\stackrel{{\mathrm{NaNH}}_2}{\to }\mathrm{C} \\ \mathrm{b}. \mathrm{Isopropyl} \mathrm{alcohol}\stackrel{{\mathrm{PBr}}_3/∆}{\to }\mathrm{D}\stackrel{{\mathrm{NH}}_3 \mathrm{excess}}{\to }\mathrm{E} \end{gathered}$$

 Major product obtained in the reaction is:

Consider the following transformation

The intermediate that can not be formed during this transformation is

Consider the following reaction

The major product is

Choose the correct option for the given reaction.

$\underset{\mathrm{Ethanol}}{{\mathrm{CH}}_3 {\mathrm{CH}}_2\mathrm{OH} } + {\mathrm{NaNH}}_2 \to \mathrm{A}+{\mathrm{NH}}_3$

When alcohol is treated with sodium amide, _____ gas is formed in this reaction.

How ether can be prepared by the reaction of sodium amide?

Write the reaction of alcohol with sodamide.

Describe the formation of protonated alocohol.

Ethoxide ion is a stronger base than hydroxide ion.

Why does alcohol not react with sodium hydroxide?

Which of the following conversion explains the acidic nature of alcohols?

The final product obtained by the reaction between alcohol and phosphorus pentachloride is: